Question 1185020
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(0,3) is one of the given points, so the equation is of the form<br>
{{{y=ax^2+bx+3}}}<br>
Use the other two given points to get two equations in a and b, then solve the pair of equations.<br>
(2,5):
{{{5=4a+2b+3}}}
{{{4a+2b=2}}}
{{{2a+b=1}}} [1]<br>
(3,-3):
{{{-3=9a+3b+3}}}
{{{9a+3b=-6}}}
{{{3a+b=-2}}} [2]<br>
Solve [1] and [2] by your favorite method....<br>