Question 1184883
The first acid solution contains 25 % acid, --x liters
the second contains 40 % -- y liters
and the third contains 85 % -- z liters
x+y+z =135-------(1)

Quantities used Concentration
25%x + 40%y + 85% z = 35% (x+y+z)

25x + 40y +85z = 35x+35y+35z
50z +5y-10x =0    --------(2)

z=2y------------------(3)

substitute z=2y 
in (1) we get x+3y =135
in (2) we get 105y-10x= =0
10x=105y
x=10.5 y

x+3y =135
substitute x=10.5 y
13.5y =135
y =10 liters

z=2y
z = 20 liters
x =105 liters


The first acid solution 25% , --105 liters
the second contains 40 % -- 10 liters
and the third contains 85 % -- 20 liters