Question 1184857
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The hyperbola x^2-y^2=16 has its center at (0,0), and the two branches open right and left.<br>
By symmetry, the points on the two branches that are closest together are when y=0.<br>
Substituting y=0 in the equation gives x=-4 and x=4, so the points on the two branches that are closest together are (-4,0) and (4,0).<br>
So the closest together the two branches of the parabola are is 8 units.<br>