Question 1184865

{{{log ((2)) = a}}}; {{{log((3) )= b }}}

express {{{log((150))}}} in terms of {{{a }}}and {{{b}}}

{{{log((150))}}}

={{{log((25*6))}}}

={{{log((5^2)) + log((6))}}}

={{{2log((5)) + log((2*3))}}}

={{{2log((5)) + log((2))+log((3))}}}

={{{2log((5)) + a+b}}}