Question 1184834
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Let the side of the square be x<br>
Then the dimensions of the rectangle are x-2 and x+3<br>
The area of the rectangle is 4 more than the area of the square:<br>
{{{(x-2)(x+3)=x^2+4}}}<br>
That equation is easily solved using basic algebra; I leave it to you to do that.<br>