Question 1184819
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Probably easier if you use a single variable....<br>
x=Alan's amount
800-x=Mike's amount<br>
1/4 of Alan’s money was $65 more than 1/5 of Mike’s money:<br>
{{{(1/4)x=(1/5)(800-x)+65}}}<br>
I would multiply through by the least common denominator (20) to make the rest of the work easier.<br>
{{{5x=4(800-x)+1300}}}<br>
I'll let you finish from there....<br>