Question 1184785
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Tutor @josgarithmetic has recently been giving a lot of responses that basically give the answer to a question without providing anything useful to the student who is trying to LEARN HOW to get the answer....<br>
One version of the vertex form of a quadratic equation is<br>
{{{(y-k)=(1/(4p))(x-h)^2}}}<br>
In that formula, (h,k) is the vertex and p is the directed distance (i.e., might be negative) from the vertex to the focus.<br>
(Note in her response she uses the equivalent form<br>
{{{(x-h)^2=4p(y-k)}}}<br>
I have a personal preference for having the linear expression on the left side of the equals sign...)<br>
In this problem we have the vertex (h,k)=(2,3), and p is the distance from (2,3) to (2,5), which is 2.  That gives us the vertex form of the equation:<br>
{{{y-3=(1/8)(x-2)^2}}}<br>
I leave it to you to convert that to standard form....<br>