Question 1184787
{{{x=-2}}}, or {{{x=10/3}}}


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Three intervals based on two critical x  values,

{{{x<-1}}}
result:  x=-2 works in the original equation.


{{{-1<x<3/2}}}
result:  {{{x=-4}}}; did not seem to work in original equation; maybe need to recheck


{{{x>3/2}}}
result:  {{{x=10/3}}} works in original equation.