Question 1184783
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Given that f(x) = 2x^2 + x - 3, write f(x) in the form a(x+b)^2 + c,where a,b and c are constants.Sketch the graph of y = |f(x)|
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f(x) = {{{2x^2 + x - 3}}} = {{{2*(x^2 + (1/2)x) - 3}}} = {{{2*(x^2 + 2*(1/4)*x + 1/16) - 2/16 - 3)}}} = {{{2*(x+1/4)^2 - 1/8 - 3}}} = {{{2*(x+1/4)^2 - 25/8}}}.


Thus a= 2, b= 1/4, c= -25/8.


Sketch the graph of y = |f(x)| on your own.
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