Question 1184744
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someone thinks he can shoot an arrow as high as the Willis Tower in Chicago (443 m high). 
(a) at what velocity would the arrow have to be released at ground level? 
(b) how long would the ascent take?
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<pre>
(a)  The general formula to calculate the required initial vertical velocity of ascent  " v "  is


         v = {{{sqrt(2gh)}}},


     where h is the maximum height in meters, g is the gravity acceleration g = 9.81 m/s^2.


     For h = 443 meters (your example)


         v = {{{sqrt(2*9.81*443)}}} = 93.229 m/s.




(b)  For the ascent time, use the formula  and get the answer


         t = {{{sqrt((2h)/g)}}} = {{{sqrt((2*443)/9.81)}}} = 9.5 seconds  (rounded).
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Solved, answered and explained.