Question 1184545


given:

a height of {{{30 }}}feet=> vertex is at ({{{0}}},{{{30}}})
and a base width of {{{40}}} feet=> since vertex at {{{x=0}}}, a base width of {{{40}}} is the distance between {{{x=-20}}} and {{{x=20}}}


Solution:

The equation is {{{y=Ax^2+30}}}

It passes ({{{0}}},{{{30}}}) and ({{{-20}}},{{{0}}}) and ({{{20}}},{{{0}}})

{{{0=A*20^2+30}}}

{{{A = -3/40}}}

So the equation is {{{y=-(3/40)x^2+30}}}