Question 1184579
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A rectangular lot is to be enclosed with an area of 160x - x^2 {{{highlight(square_meters)}}}. 
Let x meters be the length of the field, express the perimeter of the field as a function of {{{cross(X)}}} x.
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<pre>
If the area is  {{{160x - x^2}}}  and x is the length, then the width is  {{{(160x-x^2)/x}}} = 160-x  meters.


Therefore, the perimeter is


    P = 2x + 2(*160-x) = 320 meters.      <U>ANSWER</U>
</pre>

Solved.