Question 1184535

Two cruise ships depart from the same harbor. Seabourn Odyssey departs at 8 AM, and travels due south 2 mph faster than the northbound Norwegian Bliss, that left the harbor 1 hour later than Seabourn Odyssey. At noon, the ships are 176 miles apart. How fast has each ship been travelling
<pre>Let Norwegian Bliss' speed be S
Then Seabourn Odyssey's speed = S + 2
Distances covered by Norwegian Bliss and Seabourn Odyssey are: 3S and 4(S + 2), or 4S + 8, respectively
Their respective distances covered, sum to 176 miles, and so, we get the following DISTANCE equation: 3S + 4S + 8 = 176
3S + 4S = 176 - 8
7S = 168
Norwegian Bliss' speed, or {{{highlight_green(matrix(1,6, S, "=", 168/7, "=", 24, mph))}}}
Seabourn Odyssey's speed: {{{highlight_green(matrix(1,4, 24 + 2, "=", 26, mph))}}}