Question 1184481
<pre>
It will have at least 1 real solution if its discriminant is non-negative.

{{{x^2 + bx +64 = 0}}}

has discriminant

{{{b^2-4ac>=0}}}}

{{{b^2-4(1)(64)>=0}}}

{{{b^2-256>=0}}}

{{{(b-16)(b+16)>=0}}}

Solution: {{{(matrix(1,8,-infinity,",","-16]",U,"","[16",",",infinity))}}}

Edwin</pre>