Question 1184463
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A fund-raising project lasted 2 weeks.
In the 1st week, Team Cupcakes raised 4/7 as much as money as Team Drinks.
In the 2nd week, Team Cupcakes raised another $214 while Team Drinks raised another $260.
The total amount raised by Team Cupcakes was 2/3 as much as the total amount raised by Team Drinks.
What was the total amount of money raised by the two teams?
I not yet learnt algebra. Please help me to solve this problem
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            This problem is  NOT  INTENDED  for those who  " not yet learnt algebra ".

            THEREFORE,  I will  IGNORE  your note saying that you did not learn algebra,  yet.

            I will solve it as if I communicate with a person who is able to understand the subject.



                      If you do not understand - - - then it is  YOUR  problem - not mine.

                        If not you, then next generations of students will learn from my solution,  reading it in the future from the archive.



For short,  I will call the teams by letters   " C "   and   " D ".



<pre>
Since "The total amount raised by Team C was 2/3 as much as the total amount raised by Team D",

I will assume that total amount raised by D was 3x dollars, while the total amount raised by C was 2x dollars.


Then 

   the team D's raising in the 1st week  is  3x - 260  dollars,  while

   the team C's raising in the 1st week  is  2x - 214  dollars.


Based on problem's condition, we have this equation


    2x - 214 = {{{(4/7)*(3x-260)}}}.


To solve this equation, multiply both sides by 7, then simplify.


    14x - 7*214 = 12x - 4*260

    14x - 12x = 7*214 - 4*260

       2x     = 458.

        x     = 458/2 = 229.


The total amount of money raised by the two teams is then  2x + 3x = 5x = 5*229 = 1145 dollars.     <U>ANSWER</U>
</pre>

Solved.