Question 1184436
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Henry spent 1/4 of his money and an additional $3 on a number of DVDs. 
He then spent 3/5 of the remaining money and an additional $6 on a number of batteries. 
Given that he was left with $24, how much money did Henry have at first?
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            It is a nice problem to be solved backward and explained accordingly.



<pre>
First, let x be the remainder money amount after buying a number of DVDs.


Then for this amount of money you have this equation

    x - {{{((3/5)x + 6)}}} = 24.     (1)


To solve it, multiply everything in equation (1) by 5  to get

    5x - (3x + 30) = 24*5

    5x - 3x        = 24*5 + 30

       2x          = 120 + 30 = 150

        x                     = 150/2 = 75.


Thus you found that after buying a number of DVDs, the remainder was 75 dollars.


OK.     It gives you  NEXT EQUATION from the first part of the problem 

    M - {{{((1/4)M + 3)}}} = 75    (2)


where M is the unknown money amount Henry had at first.


From this equation, you get

    {{{(3/4)M}}} = 75 + 3 = 78,

        M    = {{{(78*4/3)}}} = 26*4 = 104.


<U>ANSWER</U>.  At first,  Henry had $104.
</pre>

Solved and thoroughly explained.


Check my answer on your own.