Question 1184367

vertices: ( {{{5}}},{{{0}}}) ,( {{{5}}},{{{0}}}) 

=>major (transverse) axis length: {{{2a=10}}} =>{{{a=5}}}

one focus at ({{{6}}},{{{0}}})=> other focus is at ({{{-6}}},{{{0}}}) and {{{c=6}}}

=> center: ({{{0}}},{{{0}}})

then, {{{b^2=c^2-a^2}}}
{{{b^2=6^2-5^2}}}
{{{b^2=36-25}}}
{{{b^2=11}}}

and, the equation of the hyperbola is:

{{{x^2/a^2-y^2/b^2=1}}}

{{{x^2/25-y^2/11=1}}}


{{{ drawing( 600, 600, -10, 10, -10, 10,
circle(-5,0,.12), locate(-5,0.6,V(-5,0)),
circle(5,0,.12), locate(5,0.6,V(5,0)),
circle(6,0,.12), locate(6,-0.5,F(6,0)),
graph( 600, 600, -10, 10, -10, 10, sqrt((x^2/25-1)11),-sqrt((x^2/25-1)11)) ) }}}