Question 1184285


answer is: {{{2}}} or {{{-3/2}}}

Apply {{{2g1*g2+2f 1*f 2=c1+c2}}}
​
{{{2(1)(0)+2(k)(k)=6+k }}}
 {{{2k^2=6+k }}}
 {{{2k^2-k-6=0}}}
 {{{2k^2-4k+3k-6=0}}}
{{{(2k^2-4k)+(3k-6)=0}}}
{{{2k(k-2)+3(k-2)=0}}}
{{{(k-2)(2k+3)=0}}}

=>{{{k=2}}} or {{{k=-3/2}}}