Question 1184279

Equation of the line containing the given point and perpendicular to the given line (7,-6);6x+5y=4
<pre>As the given equation is in standard form, we switch the variables' coefficients, negate the new
y-coordinate, and then substitute the given coordinates on the right side to get the constant.
In other words, 6x + 5y = 4 becomes: 5x - 6y = 5(7) - 6(- 6)
5x - 6y = 35 + 36
<b><font size = 4><font color = red>5x - 6y = 71 <==== Equation of the line sought.</font></font></b>