Question 1184276

The sum of three numbers is 114. The first number is 6 less than the third. The second number is 4 times the third. What are the numbers?
<pre>Let 3rd number be T
Then 1st is: T - 6, and 2nd = 4T
We then get: T + T - 6 + 4T = 114
6T = 114 + 6
6T = 120
3rd number, or {{{highlight_green(matrix(1,5, T, "=", 120/6, "=", 20))}}}
1st number: {{{highlight_green(matrix(1,5, T - 6, "=", 20 - 6, "=", 14))}}}
2nd number: {{{highlight_green(matrix(1,5, 4T, "=", 4(20), "=", 80))}}}