Question 1184237
{{{x^2 + (3a - 2b)x - 6ab = 0}}}

{{{x=(-b+-sqrt(b^2-4ac))/2a}}}

in your case (en tu caso):

{{{ a=1}}}
{{{b=(3a - 2b)}}}
{{{c=-6ab}}}


{{{x=(-(3a - 2b)+-sqrt((3a - 2b)^2-4*1(- 6ab)))/(2*1)}}}

{{{x=(-3a +2b+-sqrt(9a^2-12ab+4b^2+24ab))/2}}}

{{{x=(-3a +2b+-sqrt(9a^2 + 12ab + 4b^2))/2}}}

{{{x=(-3a +2b+-sqrt((3a)^2 + 12ab + (2b)^2)))/2}}}

{{{x=(-3a +2b+-sqrt((3a + 2b)^2))/2}}}

{{{x = (-3a+2b +- (3a + 2b ))/2 }}}


solutions (soluciones):

{{{x=(-3a +2b+(3a + 2b))/2}}} =>{{{x=(-3a +2b+3 a + 2b)/2}}} =>{{{x=(4b)/2}}} =>{{{x=2b }}}

{{{x=(-3a +2b-(3a + 2b))/2}}} =>{{{x=(-3a +2b-3a -2b)/2}}} =>{{{x=(-6a )/2}}} =>{{{x=-3a }}}