Question 1184229
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Use the distance formula


    {{{(x-2)^2}}} + {{{(3-1)^2}}} = 20


and find x from this equation


    {{{(x-2)^2}}} = 20 - 4 = 16


    x- 2 = +/- 4


    {{{x[1]}}} = 2 + 4 = 6;     {{{x[2]}}} = 2 - 4 = -2.


As you see from my solution, there are two such values of x, satisfying the condition.
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Solved.