Question 1184227
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the center of a circle is at (-3,2) and its radius is 7. Find the length of the chord, which is bisected at (3, 1).
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<pre>
The distance between the given points is  {{{sqrt(6^2+1^2)}}} = {{{sqrt(37)}}}.


It is the length of the leg of the right angled triangle, whose hypotenuse is 7.


THEREFORE, half of the chord's length is  {{{sqrt(7^2-37)}}} = {{{sqrt(49-37)}}} = {{{sqrt(12)}}} = {{{2*sqrt(3)}}}.


The entire chord is twice this length, or  {{{4*sqrt(3)}}}.    <U>ANSWER</U>
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Solved.