Question 1184142
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Peter had 3/8 as many marbles as Simon. After Simon misplaced 3/4 of his marbles, 
Peter had 120 more marbles than Simon. How many marbles did Peter have?
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<pre>
Let Simon = x.

Then Peter = {{{(3/8)x}}}.


The equation


    {{{(3/8)x}}} - {{{(x-(3/4)x)}}} = 120.


Simplify and find x


    {{{(3/8)x}}} - {{{(1/4)x}}} = 120

    {{{(1/8)x}}} = 120

    x = 8*120 = 960.


<U>ANSWER</U>.  Pater had  {{{(3/8)*960}}} = 3*120 = 360 marbles.
</pre>

Solved.