Question 1184071
let A = amount invested at 12%.
let B = amount invested at 14%.


your two equations that need to be solved simultaneously are:


A + B = 9000
.12A + .14B = 1110


multiply both sides of the first equation by .12 and leave the second equation as is to get:


.12A + .12B = 1080
.12A + .14B = 1110


subtract the first equation from the second to get:


.02B = 30


solve for B to get:


B = 30/.02 = 1500


since A + B = 9000, then A must be equal to 9000 - 1500 = 7500


A + B = 9000 becomes 7500 + 1500 = 9000 which is true.
.12A + .14B = 1110 becomes 900 + 210 = 1110 which is also true.


the solution is confirmed to be good.


the solution is that 7500 was loaned at 12% and 1500 was loaned at 14%.