Question 1184057


I guess you need to find {{{C}}} first.

if the general solution is

{{{y(x)= x/2+Cx^9}}}

and if {{{y(1)=2}}}, find {{{C}}}

{{{2=1/2+C*1^9}}}

{{{C = 3/2}}}

then

{{{y(x)= x/2+(3/2)x^9}}}