Question 1184038
Let L = volume of diluted cordial in jug 1

===> 2L = volume of diluted cordial in jug 2

From the given, jug 1 would be {{{(2/7)L}}} in cordial by volume and {{{(5/7)L}}} in water by volume.

Also from the given, jug 2 would be {{{(3/10)2L}}} in cordial by volume and {{{(7/10)2L}}} in water by volume.


===> then the ratio of cordial to water in the final mixture is {{{((2/7)L + (3/10)(2L))/((5/7)L + (7/10)(2L)) = (2/7 + 6/10)/(5/7 + 14/10) = 31/74}}}