Question 1184018
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Here is a very different approach to answering the question -- WITHOUT using distance = rate * time.<br>
In the 200m race, Jenny completes 190m while Susan completes 200m.  That means Jenny's speed is 19/20 of Susan's speed.<br>
So Jenny and Susan will finish a race together if the distance Susan has to run is 20/19 of the distance Jenny has to run.<br>
But in the second race, the distance Susan has to run is 210/200 = 21/20 of the distance Jenny has to run.  And 21/20 (= 1 1/20) is less than 20/19 (= 1 1/19) -- so Susan will win this race also.<br>