Question 1184034
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Curiously, the expression you show is indeed equal to -2; and the expression you undoubtedly INTENDED to show is also equal to -2.<br>
Here is the expression you show: "x-2y/2y-x + 2y-x/x-2y"<br>
{{{x-2y/2y-x + 2y-x/x-2y = (x-1-x)+(2y-1-2y) = (-1)+(-1) = -2}}}<br>
Here, on the other hand, is the expression you most probably meant: "(x-2y)/(2y-x)+(2y-x)/(x-2y)"<br>
{{{(x-2y)/(2y-x)+(2y-x)/(x-2y) = (-(2y-x))/(2y-x)+(-(x-2y))/(x-2y) = (-1)+(-1) = -2}}}<br>
If you are working problems like this, your math knowledge should be great enough to know that proper use of parentheses is important...!<br>