Question 1184033
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There are dozens of ways to set up this problem for solving....<br>
I would do some logical analysis on the given information to make the required algebra easier.  In fact my preference would be to solve the whole problem without formal algebra.<br>
(1) Since the sum of the first two numbers is twice the third number, the third number is one-third of the total.
(2) Then, since the sum of the three numbers is 15, the third number is 15/3=5.
(3) Then the sum of the first two numbers is 15-5=10.
(4) Then, since the second number is 2 less than the first, the first number is 6 and the second is 4.<br>
ANSWER: 4, 5, and 6<br>
If an algebraic solution is required, I would still do the logical analysis of (1) and (2) above to determine that the third number is 5.  Then<br>
let x = first number
then x-2=second number<br>
The sum of the three numbers is 15:<br>
{{{x+(x-2)+5=15}}}
{{{2x+3=15}}}
{{{2x=12}}}
{{{x=6}}}<br>
The first two numbers are x=6 and x-2=4; the three numbers are 4, 5, and 6.<br>