Question 111671
Calculate the discriminant of:
{{{y = x^2+x+3}}}
Since this quadratic equation is already in the standard form of: {{{y = ax^2+bx+c}}} and the discriminant is defined as: {{{b^2-4ac}}}, then:
{{{b^2-4ac = 1^2-4(1)(3)}}}={{{1-12 = -11}}} 
The discriminant is negative which means that the equation has two complex roots.
Why, because the discriminant is the quantity under the radical (square root sign) and the square root of a negative number is an imaginary number, so that the roots will be complex.
{{{x = -0.5+sqrt(11)i}}}
{{{x = -0.5-sqrt(11)i}}}
Complex roots means that the graph of the equation (a parabola) never intercepts the x-axis, as shown by the graph below:
{{{graph(600,400,-5,5,-5,5,x^2+x+3)}}}