Question 1183968
p hat, point estimate, is 405/732=0.5533
half-interval for 95% Is z(0.975)*sqrt(0.5533*0.4467/732)
=1.96*0.0184
=0.0360
the interval is  (0.5173, 0.5893)
We are highly confident that the true value the proportion of judges who are introverts lies within this interval.