Question 1183966
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In typed text, it is customary to use "^" (shift-6) to represent exponentiation.<br>
In order for your question to make sense, I believe the expression you are working with is ((x^3)(y^6))^(-(1/3)):<br>
{{{((x^3)(y^6))^(-(1/3))}}}<br>
Simplifying the expression is a matter of applying basic rules of exponents:<br>
(1) {{{(x^a)^b=x^ab}}}  (a power raised to a power: multiply the powers)<br>
(2) {{{(x^(-a))=1/(x^a)}}}  (negative power: reciprocal)<br>
For your expression...<br>
{{{((x^3)(y^6))^((1/3))=((x^3)^((1/3)))*((y^6)^((1/3)))=(x^(3*(1/3)))(y^(6*(1/3)))= xy^2}}}<br>
And so then (with the negative exponent)<br>
{{{((x^3)(y^6))^((-1/3))=1/(xy^2)}}}<br>