Question 1183929
Find an equation of the line passing through the points (3, -5) with the slope m= -3/8
:
Using the point/slope equation,  y - y1 = m(x - x1)
x1=3
y1=-5
m = -3/8
we have
y - (-5) = {{{-3/8}}}(x - 3)
y + 5 = {{{-3/8}}}x + {{{9/8}}}
y = {{{-3/8}}}x + {{{9/8}}} - 5
Change 5 to 40/8
y = {{{-3/8}}}x + {{{9/8}}} - {{{40/8}}}
:
y = {{{-3/8}}}x - {{{31/8}}}