Question 1183921
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I would solve this problem by a very different method from the similar ones used by the other two tutors; I have a particular dislike for that "product of the means equals product of the extremes" rule, since it introduces unneeded new vocabulary.<br>
Given the ratio of a:b and the ratio of a:c, and needing to find the ratio c:b, I would rewrite the second ratio as c:a; then I would "eliminate the middle man" in the ratios c:a and a:b.<br>
c:a = 7:3
a:b = 2:5<br>
rewrite each ratio as an equivalent ratio using the same number for a in both:<br>
c:a = 14:6
a:b = 6:15<br>
Combine them into a ratio comparing all three numbers...<br>
c:a:b = 14:6:15<br>
and eliminate the middle man:<br>
c:a = 14:15<br>