Question 1183914
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Find the area of the polygon with the vertices P(-5,4), Q(2,4) and S(1,-1)
Express your answer in the simplest radical form
Please note : Student is only permitted to use formula Area= 1/2 bh
Cannot use this formula Area = 1/2[x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)]
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The given polygon is a triangle.


Side PQ of this triangle is horizontal and has  2 - (-5) = 7 units length.


The altitude of this triangle drawn to side PQ is 4 - (-1) = 5 units long.


Hence, the area of this triangle is half the product of 7 and 5, i.e.  {{{(1/2)*7*5}}} = {{{(1/2)*35}}} = 17.5 square units.    <U>ANSWER</U>
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Solved.