<PRE><B>Question 1183863</B>
One angle of a triangle ABC is twice as large as another.
A = 2B
 The measure of the third angle is 84 degrees more than that of the smallest angle.
C = B + 84
:
Find the measure of each angle.
A + B + C = 180
Replace A with 2B and replace C with (B+84)
2B + B + (B+84) = 180
4B = 180 - 84
4B = 96
B = 96/4
B = 24
Then
A = 2(24) = 48 deg
C = 24 + 84 = 108 deg
:
:
Check: 48 + 24 + 108 = 180

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