Question 1183832
Graph this:
{{{graph(300,300,-3,3,-3,3,sqrt(-x^2+4),-sqrt(-x^2+4),5x-4)}}}
It should be clear from this that he would not qualify.
Finding the closest point is more work but can be done by using y=5x-4 and x^2+y^2=4
you can square y and have x^2+25x^2-40x+16=4
that will give x=0.41 and 1.13 where Maple St. intersects the 2 mile radius.
From the length of the chord (need y values) one may determine the length of the chord. Half that is the center and the closest point to the origin. Since the the length of the chord is known (one leg) and the hypotenuse is the radius, the closest point may be found, since this is a right triangle.