Question 1183804
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Please help. A calculus professor plans classes so carefully that the length of his classes is uniformly distributed 
between 100.0 min. and 105.0 min. Let x be the random variable representing the length of his randomly selected class. 
Find the probability the class is greater than 103 min.
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Yesterday I solved a TWIN problem at this link


<A HREF=https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1183789.html>https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1183789.html</A>


https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1183789.html



So, this time I will be short.



<pre>
    P = {{{(105-103)/(105-100)}}} = {{{2/5}}} = 0.4 = 40%.    <U>ANSWER</U>
</pre>

As always in such problems, you divide the "favorable" time interval length by the base interval length.


It is how the uniform distribution probability works.



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<U>Comment from student</U> : &nbsp;&nbsp;Thank you for your help! I &nbsp;checked the link and I noticed that problem was &nbsp;"less than" 
while this one is "greater than). &nbsp;So for either way, they are solved the same?



<U>My response</U> : &nbsp;&nbsp;You are right. &nbsp;The major idea is the same


    &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;P = {{{favorable_time_interval/base_time interval}}}.



The only thing is to take care to calculate the numerator and denominator correctly.