Question 1183763

 A three-digit number whose hundreds digit is twice the tens digit and the tens digit is 3 more that
the units digit
<pre>Let units digits be U
Then tens digit = U + 3, and hundreds digit is: 2T, or 2(U + 3) = 2U + 6
By observation, with the hundreds digit being 2U + 6, U or the units digit CANNOT be 2 or more. 
Therefore, U or the units digit MUST either be 0 or 1.

<u><b>First case: Units digit = 0 </u></b>
Tens digit = 0 + 3 = 3
Hundreds digit = 2(0) + 6 = 6
Number, based on the above: {{{highlight_green(630)}}}
 				
<u><b>Second case: Units digit = 1 </u></b>
Tens digit = 1 + 3 = 4
Hundreds digit = 2(1) + 6 = 8
Number, based on the above: {{{highlight_green(841)}}}</pre>