Question 1183723
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Informally....<br>
Take away the 2 "extra" 5ch coins, leaving equal numbers of 5ch and 25ch coins with a total value of nu.3.30.<br>
The value of a group consisting of one 5ch coin and one 25ch coin is 30ch.<br>
The number of such groups needed to make nu.3.30=330ch is 330/30=11.<br>
Bring back the 2 "extra" 5ch coins, giving 11 25ch coins and 13 5ch coins.<br>
ANSWER: 13 5ch coins<br>
Formally....<br>
Let x be the number of 5ch coins -- which is what we are to find
Then x-2 is the number of 25ch coins<br>
The total value of the coins is 340ch:<br>
{{{5(x)+25(x-2)=340}}}<br>
Solve using basic algebra to again find the number of 5ch coins is x=13.<br>