Question 1183712
<s>You could write two equations in k and x variables, and then,</s>
{{{cross((90-x-5)/(x-5)=4/3)}}}
<s>which should be easily solved.</s>


k and x for Kate and Sharon now;


{{{system((k-5)/(x-5)=4/3,k+x+5+5=90)}}}


{{{k+x=80}}}
{{{k=80-x}}}
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{{{(80-x-5)/(x-5)=4/3}}}--------solve this for x.