Question 1183676
Diameter with endpoints (p,v) and (q,w)
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Center point for the circle is some (h,k) and {{{h=(p+q)/2}}}, and {{{k=(v+w)/2}}}.


Radius squared is  {{{((q-p)/2)^2+((w-v)/2)^2}}}.


Equation would be {{{(x-(p+q)/2)^2+(y-(v+w)/2)^2=(q-p)^2+(w-v)^2}}}.
Using the actual values as you were given may be a little easier.


Your circle's center is  ( (-2+6)/2, (-1-3)/2 )
or (2,-2).

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{{{highlight((x-2)^2+(y+2)^2=cross(68))}}}