Question 1183630
A marketing manager for a publishing company has a 6 foot by 8 foot banner to be used when setting up booths at educational conferences.
 She decides add more zing to the booth by increasing the square footage by 50%, and plans to accomplish this by increasing each of the dimensions by the same amount.
 What will the new dimensions be?
:
Find the area of the new banner
1.5(6*8) = 72 sq/ft
Let x = the amt of increase required to accomplish this
(x+6)(x+8) = 72
FOIL
x^2 + 8x + 6x + 48 = 72
x^2 + 14x + 48 - 72 = 0
x^2 + 14x - 24 = 0
Use the quadratic formula: a=1; b=14; c=-24
I got a positive solution: 1.544 ft
:
What will the new dimensions be?
6+1.544 = 7.544 ft is the new width
8+1.544 = 9.544 ft is the new length
:
Check: 7.544 * 9.544 ~ 72 sq/ft