Question 1181930
A)  Let X = r.v. equal to shots made from a free throw situation.  The possible values of X are 0, 1, or 2.

Two-shot:  {{{P(X=0) = C(2,0)*0.7^0*0.3^2 = 0.09}}}
{{{P(X=1) = C(2,1)*0.7^1*0.3^1 = 0.42}}}, and {{{P(X=2) = C(2,2)*0.7^2*0.3^0 = 0.49}}}

1-and-1: {{{P(X=0) = 0.50}}}, {{{P(X=1) = 0.50*0.50  =0.25}}}, and {{{P(X=2) = 0.50*0.50  =0.25}}}.


B) 2-shot:   {{{E(X) = 0*0.09 + 1*0.42 + 2*0.49 = 1.4}}}
1-and-1:     {{{E(X) = 0*0.50 + 1*0.25 + 2*0.25 = 0.75}}}


C) 2-shot:   20*1.4 = 28
1-and-1:   30*0.75 = 22.5
She would be expected to score {{{highlight(50.5)}}} points from free throws that season.