Question 16682
b + 2 = 27 + 2b/ 3
First subtract 27 from each side;
b+2-27=27+{{{2b/3}}}-27
b-25={{{2b/3}}}
Now multiply each side by 3;
(3)b-25={{{2b/3}}}(3)
3b-75=2b
Add 75 to each side;
3b-75+75=2b+75
3b=2b+75
Subtract 2b from each sidel
3b-2b=2b+75-2b
b=75
Don't forget to check your answer
Hope you understand
=)