Question 1183601
if you have

{{{3^x+5=1/27}}}, then {{{x}}}=


{{{3^x=1/27-5}}}

{{{3^x=-134/27}}}......take log of both sides

{{{log(3^x)=-log(134/27)}}}

{{{x*log(3)=-(log(134)-log(27))}}}

{{{x=(-(log(134)-log(27)))/log(3)}}}

{{{x=-1.4582}}} approximately


but, if you have

{{{3^(x+5)=1/27}}} then

{{{3^(x+5)=1/3^3}}}

{{{3^(x+5)=3^-3}}}.........if bases same, exponents are same to, the we have

{{{x+5=-3}}}

{{{x=-3-5}}}

{{{x=-8}}}