Question 1183571
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Here first is another presentation of the solution provided by the other tutor.<br>
Let y be the number of years from now that her father's age will be 3 times her age.<br>
Their current ages are 14 and 46; y years from now their ages will be 14+y and 46+y.<br>
We want to know when 46+y will be 3 times (14+y):<br>
{{{46+y=3(14+y)}}}
{{{46+y=42+3y}}}
{{{4=2y}}}
{{{y=2}}}<br>
ANSWER: Her father's age will be 3 times her age in 2 years.<br>
CHECK: 14+2=16; 46+2=48; 48=3*16<br>
Here is a very different algebraic approach to solving the problem.<br>
The difference between their ages is 46-14=32 years.<br>
When the father is 3 times as old, their ages can be represented by x and 3x; the difference between their ages will be 3x-x=2x.<br>
But the difference between their ages is 32 years.  So 2x=32; x=16.<br>
The father will be 3 times as old as his daughter when their ages are x=16 and 3x=48.  Since their ages are currently 14 and 46, that will be 2 years from now.<br>
All the words of explanation make this sound like a longer and slower approach to solving the problem.  However, this method of solving the problem can be done mentally in far less time than writing and solving an equation.<br>