Question 1183527


In the equation {{{f(x)=mx+c}}}, the {{{m}}} is acting as the {{{vertical}}}{{{ stretch}}} or {{{compression}}} of the identity function, {{{c}}} shifted up or down . 

When {{{m }}}is negative, there is also a vertical reflection of the graph. 

Notice in the figure below that multiplying the equation of 
{{{f(x)=x }}}by {{{m }}} {{{stretches}}} the graph of {{{f}}} by a factor of {{{m}}} units if {{{m>1}}} and {{{compresses}}} the graph of f by a factor of{{{ m}}} units if {{{0<m<1}}}. This means the larger the absolute value of {{{m}}}, the steeper the slope.

in your case: the translation from {{{y=x}}} to{{{ y=3x+2}}}

graph is shifted up {{{2}}} units
 there is vertical stretch by a factor of {{{3}}} units