Question 1183513
 the equation of the line that:

passes through the origin ({{{0}}},{{{0}}}) and

the point ({{{-1}}},{{{14}}}) 

first find a slope {{{m}}}

{{{m=(14-0)/(-1-0)=-14}}}


use point slope formula for a line


{{{y-y[1]=m(x-x[1])}}}.......substitute {{{m=-14}}} and ({{{0}}},{{{0}}})


{{{y-0=-14(x-0)}}}

{{{y=-14x}}}-> your equation


the equation of the line that is perpendicular to this line:

the line that is perpendicular to this line will have a slope negative reciprocal to  {{{m=-14}}} and it is

 {{{m=-(1/-14)}}} 

{{{m=1/14)}}} 

use 

{{{y-y[1]=m(x-x[1])}}}.......substitute {{{m=1/14}}} and ({{{0}}},{{{0}}})

{{{y-0=(1/14)(x-0)}}}

{{{y=(1/14)x}}}->the equation of the line that is perpendicular to {{{y=-14x}}}-

{{{ drawing ( 600, 600, -15, 15, -15, 15, 
circle(-1,14,.15),locate(-2,14,p(-1,14)),
graph( 600, 600, -15, 15, -15, 15, -14x, (1/14)x)) }}}